Odds calculation bug

Update: Not a bug. See MattP's reply below.

In Poker Night 2, Texas Hold 'Em, I noticed this math error and took a screen cap. No need to reply.

1VXEOG6l.jpg

The hand is:
Player: K♠ 2♠ (93%)
Ash: 4♦ K♦ (20%)
Table: 2♥ K♣ 5♦ J♠ 10♦

Addendum:
Here's an album with more examples of the odds calc bug.

Comments

  • edited May 2013
    Here's another one, also from Poker Night 2. This time, it's Omaha, before the flop.

    Player: K♥ 7♦ A♠ J♣ (24%)
    Claptrap: A♣ 8♣ K♦ A♥ (80%)
    Table: none


    RgIrSVQl.png
  • edited May 2013
    Seen this many times, but I don't think it's a bug. It's possible for there to be a draw, and in that case both players would be 100%.
  • MattPMattP ModeratorFormer Telltale Staff
    edited May 2013
    The percentages are the likelihood that your hand can win. You may notice that if you and another character have the same hand, you'll both have the same percentage of your hand being a winning hand, even if that is 100% for both players.
  • edited May 2013
    MattP wrote: »
    The percentages are the likelihood that your hand can win. You may notice that if you and another character have the same hand, you'll both have the same percentage of your hand being a winning hand, even if that is 100% for both players.

    I see that you are correct. Thanks for the clarification; I didn't think of that.
This discussion has been closed.