Oh, sorry, I totally missed that post. I guess we posted at the same time or something? Sorry Javi. And everyone else for leading you to believe the answer was something else.
This is what bamse has done:
[IMAGE]
I followed his instructions XD It does work. Just not especially nice, and the triangles are different sizes, and two matches cross.
Thanks. I didn't have anything handy for creating a proper image before, but I have installed gpaint now.
(Three times three is nine, right? I got it right this time?)
Surely it could also be that the daughter is the doctor and the wife belongs to the chemist? Granted it would also indicate poor punctuation, but I'm allowing that to pass!
Surely it could also be that the daughter is the doctor and the wife belongs to the chemist? Granted it would also indicate poor punctuation, but I'm allowing that to pass!
I guess, but I went with the one that doesn't require me to assume bad punctuation was used I mean, you'd say "the chemist, his daughter the doctor, and his wife" in a case like that. I can't imagine why you'd have an extra "and".
So I assumed there was one "right" solution that was also "tricky" and combined the two decidedly feminine words (daughter and wife) as one person.
My first thought was that the doctor was the daughter and she had a wife, but it said "his wife" so I scratched the idea, and put the daughter/wife as the same person with an indeterminate job.
It's so terrible I can't say it, The Highway... okay, I'll try... cucumber cut l-l-l... I can't! I just can't! It's inhumane, I almost fainted when I saw that picture...
Hahahahahaha! LOL! Who would cut a cucumber lengthwise? Tee hee ha hoo ho... *snort* titter titter giggle hee hee hoo... Ohhh... *sigh* Lengthwise... Tee hee...
Ok. So there's a 10x10 grid. You and another player play a game.
The first player to play places a coin on any square on the grid, and then each player on his turn moves the coin either up, down, left, or right.
The first player to place the coin on a square that was already played, loses.
Are you first to play or second, and which technique will you use to win?
To be honest I don't know the answer to this one but my math teacher will give me a chocolate bar if I solve it! So gimme the answer!
Ok. So there's a 10x10 grid. You and another player play a game.
The first player to play places a coin on any square on the grid, and then each player on his turn moves the coin either up, down, left, or right.
The first player to place the coin on a square that was already played, loses.
Are you first to play or second, and which technique will you use to win?
To be honest I don't know the answer to this one but my math teacher will give me a chocolate bar if I solve it! So gimme the answer!
Edit: Oh, and 11x11 grid
Quick question: Does the first player to play place the coin *and* make the first move, or is placing the coin his 'move' and the second player gets to make the first move?
Split the whole grid up into 2x2 squares. Imagine 1 of these 2x2 squares.
If your opponent is the first to move into a square ("crossing off" one of the boxes) then you have another square to go to. If your tactic is then to stay within that square, then we are left with a 1x2 rectangle that's not crossed off - if your opponent goes in one square, you can always go to the other.
So, if your opponent is the first one in a 2x2 square, you move to another square in that 2x2
If your opponent crosses off the third square in a 2x2, you cross off the fourth.
This way, you always have a move, and so the opponent must lose, if you are the person who crosses off the second square. If the first player places and then moves, then this method means the first player wins, if the first player places, then second player moves, this method means the second player wins.
Think I've solved B as well. The important thing to be familiar with is the idea that winning in this game is the same as avoiding loss.
OK for the 11x11 board. Imagine the 10x10 board cut away from it. We already know that it is impossible to lose on that bit of the board if we follow the rules for it set out in A. We are left with an L shape. Or a 1x11 rectangle and a 1x10 rectangle. Split the 1x10 rectangle into 5 1x2 domino shapes. Whenever he goes on one of the 1x2 squares, you go onto the other. You can never lose on that 1x10 rectangle.
For the 1x11 rectangle, do the same, and you're left with 1 square left over.
To win, be the first player and choose that square first.
To sum up, on mxn grids with even numbers, second player wins.
On mxn grids with odd numbers, first player wins, by chosing a corner square to start on.
Heres a riddle I just learned(might be easy but dont care)
Its a 7 letter word
it preceded God
it is greater than God
it is eaviler than the devil
poor people have it
rich people need it
and if you eat it you die.
Maybe they would have asked "do what on purpose?" to which I probably would have said "oh, nothing".
I was worried what you had said in quotes might reveal the answer but it turned out you revealed nothing(ok people you are now idiots if you cant solve it by now.
Sam goes into a clothing store with the intention of buying a new coat. However, he doesn't know his size, and there are, let's say 2,000, different coat sizes in the store. What is the minimum number of times Sam has to take a coat off before he finds one that fits him? All coats in the store have tags on them denoting the sizes. And, just so you know, this is the Sam I mean:
Lagomorph not included. His brain is gone!
So, in summary:
Sam go to store
How many times must he take off coats to find his size?
Comments
There's another, an easy one:
The chemist and his daughter, the doctor and his wife, ate nine pears and they got three each.
(Sorry if the sentence is a bit odd, it's the translation from the Spanish poem for the riddle)
(Three times three is nine, right? I got it right this time?)
Thanks. I didn't have anything handy for creating a proper image before, but I have installed gpaint now.
Yay!
Surely it could also be that the daughter is the doctor and the wife belongs to the chemist? Granted it would also indicate poor punctuation, but I'm allowing that to pass!
I guess, but I went with the one that doesn't require me to assume bad punctuation was used
So I assumed there was one "right" solution that was also "tricky" and combined the two decidedly feminine words (daughter and wife) as one person.
My first thought was that the doctor was the daughter and she had a wife, but it said "his wife" so I scratched the idea, and put the daughter/wife as the same person with an indeterminate job.
No... but... no-one would EVER do that. They're *insane*! Blasphemous!
You need to provide a specific detail
You obviously havent played 302
Oh no you didn't!
The first player to play places a coin on any square on the grid, and then each player on his turn moves the coin either up, down, left, or right.
The first player to place the coin on a square that was already played, loses.
Are you first to play or second, and which technique will you use to win?
To be honest I don't know the answer to this one but my math teacher will give me a chocolate bar if I solve it! So gimme the answer!
Edit: Oh, and
Quick question: Does the first player to play place the coin *and* make the first move, or is placing the coin his 'move' and the second player gets to make the first move?
Split the whole grid up into 2x2 squares. Imagine 1 of these 2x2 squares.
If your opponent is the first to move into a square ("crossing off" one of the boxes) then you have another square to go to. If your tactic is then to stay within that square, then we are left with a 1x2 rectangle that's not crossed off - if your opponent goes in one square, you can always go to the other.
So, if your opponent is the first one in a 2x2 square, you move to another square in that 2x2
If your opponent crosses off the third square in a 2x2, you cross off the fourth.
This way, you always have a move, and so the opponent must lose, if you are the person who crosses off the second square. If the first player places and then moves, then this method means the first player wins, if the first player places, then second player moves, this method means the second player wins.
It works for all nxm where n and m are even.
I'm going to have to see if that works...
good job
OK for the 11x11 board. Imagine the 10x10 board cut away from it. We already know that it is impossible to lose on that bit of the board if we follow the rules for it set out in A. We are left with an L shape. Or a 1x11 rectangle and a 1x10 rectangle. Split the 1x10 rectangle into 5 1x2 domino shapes. Whenever he goes on one of the 1x2 squares, you go onto the other. You can never lose on that 1x10 rectangle.
For the 1x11 rectangle, do the same, and you're left with 1 square left over.
To win, be the first player and choose that square first.
To sum up, on mxn grids with even numbers, second player wins.
On mxn grids with odd numbers, first player wins, by chosing a corner square to start on.
Its a 7 letter word
it preceded God
it is greater than God
it is eaviler than the devil
poor people have it
rich people need it
and if you eat it you die.
That actually does sound like you know the answer to my riddle.
I have to ask, did you do that on purpose?
Of course!
I am glad you did that on purpose or that would have been wierd.
Maybe they would have asked "do what on purpose?" to which I probably would have said "oh, nothing".
I was worried what you had said in quotes might reveal the answer but it turned out you revealed nothing(ok people you are now idiots if you cant solve it by now.
Sam goes into a clothing store with the intention of buying a new coat. However, he doesn't know his size, and there are, let's say 2,000, different coat sizes in the store. What is the minimum number of times Sam has to take a coat off before he finds one that fits him? All coats in the store have tags on them denoting the sizes. And, just so you know, this is the Sam I mean:
Lagomorph not included. His brain is gone!
So, in summary:
Sam go to store
How many times must he take off coats to find his size?